IMU CETChemistryStates of Matter
🧪 Chemistry

States of Matter

20 marks in IMU CET
45 questions in bank
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📖 What IMUCET Tests from States of Matter

Listen up, junior. On a 300,000-tonne VLCC (Very Large Crude Carrier), understanding how gases behave under pressure isn't just textbook chemistry—it is what keeps the ship from blowing up. Whether we are managing the Inert Gas System (IGS) to keep cargo tanks safe, or handling liquefied gas cargoes under pressure, the laws of states of matter are our daily bread and butter. For IMUCET, this topic is a high-yield zone where you can bag easy marks if your fundamentals are rock solid.

In the engine room and on deck, we deal with real gases, not just the perfect, imaginary 'ideal' ones. You need to understand how temperature, pressure, and volume interact, and why real gases deviate from ideal behavior when the pressure gets high or the temperature drops. Most students lose marks because they forget to convert Celsius to Kelvin, or they get confused between the physical meanings of the Van der Waals constants 'a' and 'b'. Keep it simple, focus on the physical meaning behind the equations, and you will breeze through these questions.

🎯 IMUCET Focus
IMUCET specifically targets direct formula-based numericals on the Combined Gas Law and Dalton's Law of Partial Pressures. They also love conceptual questions on the Van der Waals equation—specifically the physical significance of constants 'a' and 'b', the compressibility factor Z under different pressure conditions, and the formulas for critical constants (Tc, Pc, Vc). They do not ask for long derivations; they want to see if you know which formula to apply and how to do the math quickly.
MARKS WEIGHTAGE
2-3 questions
🧠 Key Concepts
Combined Gas Law
The formula (P1 * V1) / T1 = (P2 * V2) / T2 is used when a gas undergoes a change in conditions. Always convert temperature to Kelvin by adding 273.15 to the Celsius value before calculating.
Van der Waals Constants 'a' and 'b'
Constant 'a' measures the magnitude of intermolecular attractive forces, while 'b' represents the co-volume or excluded volume, which is equal to 4 times the actual volume of the gas molecules (b = 4 * Vm).
Compressibility Factor (Z)
Z = (P * Vm) / (R * T). For an ideal gas, Z = 1; at very high pressures, real gases have Z = 1 + (P * b) / (R * T) because molecular volume dominates.
Critical Temperature (Tc)
Tc = (8 * a) / (27 * R * b). It is the maximum temperature at which a gas can be liquefied by pressure alone; above Tc, it remains a gas no matter how much pressure you apply.
⚡ What to Skip
If your exam is just two weeks away, you can safely skip the detailed mathematical derivations of the Maxwell-Boltzmann distribution of molecular speeds and the complex liquid state properties like surface tension and viscosity calculations. Just memorize the definitions of viscosity and surface tension, and focus your energy on gas laws and Van der Waals constants.
🏆 Exam Strategy
First, always write down the temperature in Kelvin immediately—using Celsius is the number one trap in gas law problems. Second, remember that the Van der Waals constant 'a' is directly related to how easily a gas can be liquefied; higher 'a' means stronger attraction and easier liquefaction. Third, use the approximation R = 0.0821 L atm / (mol K) as roughly 1/12 to make mental division much faster during the exam.
🌳 Understand This Topic in Depth▼ Expand
📊 Visual Reference
Pressure (P)Compressibility Factor (Z)Z = 1 (Ideal Gas)H2 / He (Z > 1)Real Gases (CO2, N2, CH4)Low PHigh PZ < 1 (Attractive forces dominate)Z > 1 (Repulsive forces dominate)
This graph shows the Compressibility Factor (Z) versus Pressure (P) for ideal and real gases, illustrating how real gases deviate from ideal behavior (Z = 1) at different pressures.
✏️ Worked Example
A nitrogen cylinder used for purging a cargo pipeline has a volume of 10.0 L at 27 degrees C and a pressure of 15.0 atm. If the cylinder is moved to a cold storage area at -3 degrees C, what will be the pressure of the gas inside the cylinder?
Speed Tip
Notice the temperature ratio: 270/300 is exactly 0.9. Instead of doing heavy division, just multiply 15 by 0.9 directly to get 13.5 in under 10 seconds.
✅ Quick Check — Before You Practice

Answer these 3 questions to confirm you understood the key concepts above.

Q1. What is the relationship between the Van der Waals constant 'b' (co-volume) and the actual volume of the gas molecules (Vm) per mole?
A. b = Vm
B. b = 2 * Vm
C. b = 4 * Vm
D. b = (1/2) * Vm
Q2. At very high pressures, what is the simplified Van der Waals equation of state for one mole of a real gas?
A. PV = RT - a/V
B. PV = RT + Pb
C. PV = RT
D. P(V - b) = RT
Q3. Under which of the following conditions does a real gas behave most like an ideal gas?
A. High pressure and low temperature
B. Low pressure and high temperature
C. High pressure and high temperature
D. Low pressure and low temperature
🌳 Understand This Topic in Depth▼ Expand
📝 Practice Questions — States of Matter
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